(2a^2+7a-10)(a-5)=0

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Solution for (2a^2+7a-10)(a-5)=0 equation:


Simplifying
(2a2 + 7a + -10)(a + -5) = 0

Reorder the terms:
(-10 + 7a + 2a2)(a + -5) = 0

Reorder the terms:
(-10 + 7a + 2a2)(-5 + a) = 0

Multiply (-10 + 7a + 2a2) * (-5 + a)
(-10(-5 + a) + 7a * (-5 + a) + 2a2 * (-5 + a)) = 0
((-5 * -10 + a * -10) + 7a * (-5 + a) + 2a2 * (-5 + a)) = 0
((50 + -10a) + 7a * (-5 + a) + 2a2 * (-5 + a)) = 0
(50 + -10a + (-5 * 7a + a * 7a) + 2a2 * (-5 + a)) = 0
(50 + -10a + (-35a + 7a2) + 2a2 * (-5 + a)) = 0
(50 + -10a + -35a + 7a2 + (-5 * 2a2 + a * 2a2)) = 0
(50 + -10a + -35a + 7a2 + (-10a2 + 2a3)) = 0

Combine like terms: -10a + -35a = -45a
(50 + -45a + 7a2 + -10a2 + 2a3) = 0

Combine like terms: 7a2 + -10a2 = -3a2
(50 + -45a + -3a2 + 2a3) = 0

Solving
50 + -45a + -3a2 + 2a3 = 0

Solving for variable 'a'.

The solution to this equation could not be determined.

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